I was wishing to experiment the handling of cookies, but because my script doesnt want to understand this simple command: <?php setcookie("test_cookie", "some_value"); ?> I have not been able to deal w/cookies, could u tell me please, what I'm doing wrong. :cry: I f...
Forget what I said, I found the origin of my problem... DREAMWEAVER MX :!: this program sometimes I dont know why, but it generates lines of PHP code that u dont need, lines that u even havent typed, I what I have realized is that once u use the function 'mysql_fetch_array' over one variable storing...
I did exactly what u told me phpScott, I even pasted ur code into my page, but what I got was the same result... the first element of the query is not appearing :evil: this is so stupid, that is not working, I dont know what's bad. I did as well what volka recommeded me, I and tried to exclude this ...
what's inbetween? <!-- somewhere must be a mysql_query --> ... what's here? ... while ($row_processors = mysql_fetch_array($rs_processors)) ok, volka, here is the rest of the code: <?php $query_rs_processors = "SELECT brand, name, price FROM products WHERE categoria LIKE '...
This code is not showing the firs element of my query: <?php <select name="processors" id="processors"> <? while ($row_processors = mysql_fetch_array($rs_processors)) {?> <option> <? echo $row_processorsї'brand']; ...
What could be causing this problem at the client side ? http://www.boomspeed.com/rax369/error_web01.gif I have tested my page at the server side thousand of times and I have never had, that buggy message. I dont have idea to what line of code refers that "line 48" expected ")" HE...
thx phpScott, for ur help, I did that validation, coz' I need some piece of code that doesnt allow the user go to the 'final check page' (where the customer checks the products requested from the provider X) leaving some drop down menu without a product choosen and specifying its quantity, and vicev...
I had already located my problem twigletmac thx for the code, is at this part: :evil: <?php //here begins the problematic validation code if ($GO == 1) { for ($i = 0; $i <= 9; $i++) { if ( is_numeric($products_cantї$i]) && $products_cantї$i] >...
ok, twigletmac I followed, ur advice, and I changed is_int for is_numeric, but my code, continues, not working at all. Watch how my code looks like now: $GO = 1; for ($i = 0; $i <= 9; $i++) { if (($productsї$i] == "Choose Product / Remove Product") && ($products_...
or post some more code so i can see if its a different problem ok, here u go, this is my complete validation code: $GO = 1; for ($i = 0; $i <= 9; $i++) { if (($productsї$i] == "Choose Product / Remove Product") && ($products_cantї$i] != "")) ...