Im trying to run a simple if command and this doesnt seem to work im trying to get it to hiighlight the option already selected in the db any ideas why?
function selected()
{
global $selectedno;
//for loop to loop through 10
$a = 11;
for ($i = 0; $i <10; $i++)
{
$a = --$a;
$num = $a;
if ($selectedno == $num)
{
$bash = ' selected="selected"';
}
echo '<option value="' . $a . '"' . $bash . '>' . $a . ' ' . $selectedno . ' </option>';
}
}
i cant get it to output
Moderator: General Moderators
Re: i cant get it to output
The way your function was setup once $bash is defined as SELECTED the echo would always print SELECTED. Either undefine $bash when it isn't in use or just echo something differently like below:
FYI -- you can also run your for loop from 10 to 0 with $i-- and skip the whole $a thing you're doing. I also don't think you want $selectedno echoed everytime so I modified the echo. You can also drop the use of $num and just use $a too. And one last thing, instead of using a global, why not pass the selectedno to the function?
Code: Select all
function selected()
{
global $selectedno;
//for loop to loop through 10
$a = 11;
for ($i = 0; $i <10; $i++)
{
$a = --$a;
$num = $a;
if ($selectedno == $num)
{
echo '<option value="' . $a . '" SELECTED>' . $a . ' </option>';
}
else
{
echo '<option value="' . $a . '">' . $a . ' </option>';
}
}
}