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how to get filename from multiple form file input type?

Posted: Mon Sep 21, 2009 2:31 am
by chennaibala
<?php

// make a note of the current working directory relative to root.
$directory_self = str_replace(basename($_SERVER['PHP_SELF']), '', $_SERVER['PHP_SELF']);

// make a note of the location of the upload handler
$uploadHandler = 'http://' . $_SERVER['HTTP_HOST'] . $directory_self . 'multiple.upload.php';

// set a max file size for the html upload form
$max_file_size = 30000000000; // size in bytes

// now echo the html page
?><!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01//EN"
"http://www.w3.org/TR/html4/strict.dtd">

<html lang="en">
<head>
<meta http-equiv="content-type" content="text/html; charset=iso-8859-1">

<link rel="stylesheet" type="text/css" href="stylesheet.css">

<title>Upload form</title>

</head>

<body>

<form id="Upload" action="<?php echo $uploadHandler ?>" enctype="multipart/form-data" method="post">

<h1>
Upload form
</h1>

<p>
<input type="hidden" name="MAX_FILE_SIZE" value="<?php echo $max_file_size ?>">
</p>

<p>
<label for="file1">File to upload:</label>
<input id="file1" type="file" name="file[]">
</p>

<p>
<label for="file2">File to upload:</label>
<input id="file2" type="file" name="file[]">
</p>

<p>
<label for="file3">File to upload:</label>
<input id="file3" type="file" name="file[]">
</p>

<p>
<label for="submit">Press to...</label>
<input id="submit" type="submit" name="submit" value="Upload us!">
</p>

</form>


</body>

</html>

<?php

// make a note of the current working directory, relative to root.
$directory_self = str_replace(basename($_SERVER['PHP_SELF']), '', $_SERVER['PHP_SELF']);

// make a note of the directory that will recieve the uploaded files
$uploadsDirectory = $_SERVER['DOCUMENT_ROOT'] . $directory_self . 'uploaded_files/';

// make a note of the location of the upload form in case we need it
$uploadForm = 'http://' . $_SERVER['HTTP_HOST'] . $directory_self . 'multiple.upload.php';

// make a note of the location of the success page
$uploadSuccess = 'http://' . $_SERVER['HTTP_HOST'] . $directory_self . 'upload.success.php';

// name of the fieldname used for the file in the HTML form
$fieldname = 'file';

//echo'<pre>';print_r($_FILES);exit;



// Now let's deal with the uploaded files

// possible PHP upload errors
$errors = array(1 => 'php.ini max file size exceeded',
2 => 'html form max file size exceeded',
3 => 'file upload was only partial',
4 => 'no file was attached');

// check the upload form was actually submitted else print form
if(isset($_POST['submit']))
{
// or error('the upload form is neaded', $uploadForm);

// check if any files were uploaded and if
// so store the active $_FILES array keys
$active_keys = array();
foreach($_FILES[$fieldname]['name'] as $key => $filename)
{
if(!empty($filename))
{
$active_keys[] = $key;
}
}

// check at least one file was uploaded
count($active_keys)
or error('No files were uploaded', $uploadForm);

// check for standard uploading errors
foreach($active_keys as $key)
{
($_FILES[$fieldname]['error'][$key] == 0)
or error($_FILES[$fieldname]['tmp_name'][$key].': '.$errors[$_FILES[$fieldname]['error'][$key]], $uploadForm);
}

// check that the file we are working on really was an HTTP upload
foreach($active_keys as $key)
{
@is_uploaded_file($_FILES[$fieldname]['tmp_name'][$key])
or error($_FILES[$fieldname]['tmp_name'][$key].' not an HTTP upload', $uploadForm);
}

// validation... since this is an image upload script we
// should run a check to make sure the upload is an image
foreach($active_keys as $key)
{
@getimagesize($_FILES[$fieldname]['tmp_name'][$key])
or error($_FILES[$fieldname]['tmp_name'][$key].' not an image', $uploadForm);
}

// make a unique filename for the uploaded file and check it is
// not taken... if it is keep trying until we find a vacant one
foreach($active_keys as $key)
{
$now = time();
while(file_exists($uploadFilename[$key] = $uploadsDirectory.$now.'-'.$_FILES[$fieldname]['name'][$key]))
{
$now++;
}
}

// now let's move the file to its final and allocate it with the new filename
foreach($active_keys as $key)
{
@move_uploaded_file($_FILES[$fieldname]['tmp_name'][$key], $uploadFilename[$key])
or error('receiving directory insuffiecient permission', $uploadForm);
}

// If you got this far, everything has worked and the file has been successfully saved.
// We are now going to redirect the client to the success page.
header('Location: ' . $uploadSuccess);

// make an error handler which will be used if the upload fails
function error($error, $location, $seconds = 5)
{
header("Refresh: $seconds; URL=\"$location\"");
echo '<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01//EN"'."\n".
'"http://www.w3.org/TR/html4/strict.dtd">'."\n\n".
'<html lang="en">'."\n".
' <head>'."\n".
' <meta http-equiv="content-type" content="text/html; charset=iso-8859-1">'."\n\n".
' <link rel="stylesheet" type="text/css" href="stylesheet.css">'."\n\n".
' <title>Upload error</title>'."\n\n".
' </head>'."\n\n".
' <body>'."\n\n".
' <div id="Upload">'."\n\n".
' <h1>Upload failure</h1>'."\n\n".
' <p>An error has occured: '."\n\n".
' <span class="red">' . $error . '...</span>'."\n\n".
' The upload form is reloading</p>'."\n\n".
' </div>'."\n\n".
'</html>';
exit;
} // end error handler
}

?>

using above program.i need to get uploaded image name with extension and store into mysql table.above coding work when i assign all file type named as file[];if i use three different file name,it showing error..
am getting textbox values like
$filepic=$_POST["file"];
i can able to get only first image file name.i cannot get other two file name.pls guide me..thanks in advance....

Re: how to get filename from multiple form file input type?

Posted: Mon Sep 21, 2009 3:19 am
by dejvos
Hello,

I'm not sure you can use "name=file[]" statement, I think you have to write array with indexes name="file[1]".

Re: how to get filename from multiple form file input type?

Posted: Mon Sep 21, 2009 5:49 am
by jackpf
Also....you should read the rules. Please post code in

Code: Select all

tags.