Day of week
Posted: Tue Oct 06, 2009 9:28 am
I am using PHP version 5.0.5
I have a varaible ($DATE (date format yyyy-mm-dd)) that is being incremented to populate a table with each day of the month. I am then trying to get the day of week (preferably an integer) for each date in the month. I have tried both
$DOW = date("w", $Date)
and
$DOW = date("l", $Date)
Using October of this year however $DOW always returns either "3" or "Wednesday". I have checked and the varaible $Date is incrementing correctly. Here is the code snippet:
for ($num = 1; $num <= $Count; $num++) {
if($num < 10)
$SDPart = "0$num";
else
$SDPart = "$num";
$Date = "2009" . "-" . $SDMo . "-" . $SDPart;
$DOW = date("w", $Date);
I have a varaible ($DATE (date format yyyy-mm-dd)) that is being incremented to populate a table with each day of the month. I am then trying to get the day of week (preferably an integer) for each date in the month. I have tried both
$DOW = date("w", $Date)
and
$DOW = date("l", $Date)
Using October of this year however $DOW always returns either "3" or "Wednesday". I have checked and the varaible $Date is incrementing correctly. Here is the code snippet:
for ($num = 1; $num <= $Count; $num++) {
if($num < 10)
$SDPart = "0$num";
else
$SDPart = "$num";
$Date = "2009" . "-" . $SDMo . "-" . $SDPart;
$DOW = date("w", $Date);