online xam
Posted: Sun Feb 21, 2010 1:14 pm
hii
i want 2 create a online xam sytem using php & mysql
the question r stored in xcel file & by using php & Ajax the question r displayed
each buttons denotes a question & the value of the button is the question number
there are 2 forms
1 for diplaying the questions & another for answering the questions
now the basic problem is i cant get the qstn number from 2nd form bcoz the qstn number is in another form
i know i cant xpress the whole thing
but i am waiting for some help
thnks in advance
i want 2 create a online xam sytem using php & mysql
the question r stored in xcel file & by using php & Ajax the question r displayed
each buttons denotes a question & the value of the button is the question number
there are 2 forms
1 for diplaying the questions & another for answering the questions
Code: Select all
<html>
<head>
<script type="text/javascript">
function sendRequest(f1) //displaying the question
{
var url = "test.php?ch="+f1;
qtn = new XMLHttpRequest();
qtn.open("GET",url,false);
qtn.send(null);
document.getElementById('show').innerHTML= qtn.responseText;
}
function store(f2) //storing the answer in database
{
var url = "db.php";
qtn1 = new XMLHttpRequest();
qtn1.open("GET",url,false);
qtn1.send(null);
}
</script>
</head>
<body>
<form name="frm" method="get">
<table border=2 allign="left">
<tr>
<td><input type="button" value="1" name="ch" onClick="sendRequest(this.value)" ></td>
<td><input type="button" value="2" name="ch" onClick="sendRequest(this.value)"></td>
</tr>
<tr>
<td><input type="button" value="3" name="ch" onClick="sendRequest(this.value)" ></td>
<td><input type="button" value="4" name="ch" onClick="sendRequest(this.value)" ></td>
</tr>
</table>
</form>
<form name="frm2" method="get">
<span id="show"></span>
<input type="submit" value="Submit" onClick="store(this.value)" >
<input type="reset" value="Reset">
<input type="submit" value="Skip">
</form>
</body>
</html>i know i cant xpress the whole thing
but i am waiting for some help
thnks in advance