Page 1 of 1

adding days to date

Posted: Tue Mar 16, 2010 10:32 pm
by Da_Elf
ive got a date stored in a database as 3 different field. YYYY, MM and DD

i did this just as a test hopeing to see it add 2,3,4 days onto the day stored in the database

Code: Select all

$querz = "SELECT * FROM event WHERE event_ID = '00000000000000000001' " ;
$resulz = mysql_query($querz, $dbConn) or die ( "Error in query: $query. " . mysql_error() );
$rolt=mysql_fetch_array($resulz);
$compedate = $rolt['event_dateey'].$rolt['event_dateem'].$rolt['event_dateed'];
$NewDate1=Date('Ymd', strtotime("+2 days",$compedate));
$NewDate2=Date('Ymd', strtotime("+3 days",$compedate));
$NewDate3=Date('Ymd', strtotime("+4 days",$compedate));
echo $compedate."<br>";
echo $NewDate1."<br>";
echo $NewDate2."<br>";
echo $NewDate3."<br>";
what i get echoed back
20100326 <---date compiled from whats in the database
19700823 <---no idea
19700824 <---more clueless
19700825 <----- utterly lost

Re: adding days to date

Posted: Tue Mar 16, 2010 11:02 pm
by John Cartwright
Try

Code: Select all

 
echo date("M-d-Y", mktime(0, 0, 0, $rolt['event_dateem'], $rolt['event_dateed'], $rolt['event_dateey']) + 172800);
echo date("M-d-Y", mktime(0, 0, 0, $rolt['event_dateem'], $rolt['event_dateed'], $rolt['event_dateey']) + 259200);
echo date("M-d-Y", mktime(0, 0, 0, $rolt['event_dateem'], $rolt['event_dateed'], $rolt['event_dateey']) + 345600);
 

Re: adding days to date

Posted: Tue Mar 16, 2010 11:08 pm
by flying_circus
Try something like this.

Code: Select all

$querz = "SELECT * FROM event WHERE event_ID = '00000000000000000001' " ;
$resulz = mysql_query($querz, $dbConn) or die ( "Error in query: $query. " . mysql_error() );
$rolt=mysql_fetch_array($resulz);
$compedate = mktime(0,0,0,(int) $rolt['event_dateem'],(int) $rolt['event_dateed'],(int) $rolt['event_dateey']);
$NewDate1=Date('Ymd', strtotime("+2 days",$compedate));
$NewDate2=Date('Ymd', strtotime("+3 days",$compedate));
$NewDate3=Date('Ymd', strtotime("+4 days",$compedate));
echo $compedate."<br>";
echo $NewDate1."<br>";
echo $NewDate2."<br>";
echo $NewDate3."<br>";
Edit: You're on it tonight, John :mrgreen: