Having issues getting Echo to display...
Posted: Wed Apr 28, 2010 2:05 pm
I'm not sure if I have a var wrong or my array's setup incorrectly, but this is what I have coded so far:
It runs the script, but doesn't display anything.
I'm a noob I know... haha.. but we all must start somewhere.
Code: Select all
<?php
$alpha = array('b','c','d','f','g','h','j','k','l','m','n','p','q','r','s','t','v','w','x','z');
$alpha2 = array('a','e','i','o','u','y');
$alpha3 = array('b','c','d','f','g','h','j','k','l','m','n','p','q','r','s','t','v','w','x','z');
$alpha4 = ('i');
$alpha5 = ('o');
$extension = '.com <br />';
for ($i=0; $i<19; $i++)
{
for ($j=0; $j<6; $j++)
{
for ($k=0; $k<19; $k++)
{
for ($l=0; $l<0; $l++)
{
for ($m=0; $m<0; $m++)
{
echo $alpha[$i] . $alpha2[$j] . $alpha3[$k] . $alpha4[$l] . $alpha5[$m] . $extension . "\n";
}
}
}
}
}
?> I'm a noob I know... haha.. but we all must start somewhere.