using variables outside of a function
Posted: Tue Aug 10, 2010 12:34 am
Hi - I have been playing with the following code (taken from http://php.net/manual/en/function.explode.php)
How do I put the words "This" and "sentence" in separate variables that I can use OUTSIDE of the function?
If I write the following:
it outputs "This" and "sentence" but if I want to pass the $firstword outside of the function, it fails.
Any idea how I can use the $firstword variable?
Cheers,
Alski
Code: Select all
<?php
print_r(explodeX(Array(".","!"," ","?",";"),"This.sentence?contains wrong;characters"));
// Returns:
// Array("This","sentence","contains","wrong","characters")
function explodeX($delimiters,$string)
{
$return_array = Array($string); // The array to return
$d_count = 0;
while (isset($delimiters[$d_count])) // Loop to loop through all delimiters
{
$new_return_array = Array();
foreach($return_array as $el_to_split) // Explode all returned elements by the next delimiter
{
$put_in_new_return_array = explode($delimiters[$d_count],$el_to_split);
foreach($put_in_new_return_array as $substr) // Put all the exploded elements in array to return
{
$new_return_array[] = $substr;
}
}
$return_array = $new_return_array; // Replace the previous return array by the next version
$d_count++;
}
return $return_array; // Return the exploded elements
}
?>
How do I put the words "This" and "sentence" in separate variables that I can use OUTSIDE of the function?
If I write the following:
Code: Select all
}
//return $return_array; // Return the exploded elements
$firstword = $return_array[0];
$secondword = $return_array[1];
echo $firstword;
echo $secondword;
}
Any idea how I can use the $firstword variable?
Cheers,
Alski