Not understanding a lin of a script.
Posted: Sun Jan 09, 2011 3:03 pm
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$name = isset($_GET['name']) ? $_GET['name'] : "";Code: Select all
$name = isset($_GET['name'])Code: Select all
? $_GET['name'] : "";A community of PHP developers offering assistance, advice, discussion, and friendship.
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$name = isset($_GET['name']) ? $_GET['name'] : "";Code: Select all
$name = isset($_GET['name'])Code: Select all
? $_GET['name'] : "";Code: Select all
$name = isset($_GET['name']) ? $_GET['name'] : "";Code: Select all
if (isset($_GET['name'])){
$name = $_GET['name'];
} else {
$name = "";
}Code: Select all
$number = isset($_POST['fnumber']) ? $number = 0;Incorrect, that code would result in a syntax error I believe, as it's missing the second value.Crux wrote:So the following would be a correct statement to give the variable number the value of 5 if no input has been given by a user in the field of a form?Code: Select all
$number = isset($_POST['fnumber']) ? $number = 0;
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$number = isset($_POST['fnumber']) ? $_POST['fnumber'] : 5;