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To access that file you will have to be connected to the internet
I read this tip in the manual under the get_file_contents() description, maybe this is causing the error
The Manual wrote:A URL can be used as a filename with this function if the fopen wrappers have been enabled. See fopen() for more details on how to specify the filename and List of Supported Protocols/Wrappers for a list of supported URL protocols.
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