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Php upload script

Posted: Thu Jan 05, 2012 7:58 pm
by Nyene
Hi Everybody. I need help on PHP image UPLOAD SCRIPT that can be printed on the same page after upload.

Re: Php upload script

Posted: Thu Jan 05, 2012 11:45 pm
by coolpriya073
hi, check this out

<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>Image Upload</title>
</head>

<body>



<?php
define ("MAX_SIZE","100");

function getExtension($str) {
$i = strrpos($str,".");
if (!$i) { return ""; }
$l = strlen($str) - $i;
$ext = substr($str,$i+1,$l);
return $ext;
}

$errors=0;
if(isset($_POST['Submit']))
{
$image=$_FILES['image']['name'];
if ($image)
{
$filename = stripslashes($_FILES['image']['name']);
$extension = getExtension($filename);
$extension = strtolower($extension);
if (($extension != "jpg") && ($extension != "jpeg") && ($extension != "png") && ($extension != "gif"))
{
echo '<h1>Unknown extension!</h1>';
$errors=1;
}
else
{
$size=filesize($_FILES['image']['tmp_name']);

if ($size > MAX_SIZE*1024)
{
echo '<h1>You have exceeded the size limit!</h1>';
$errors=1;
}

$image_name=time().'.'.$extension;
$newname="images/".$image_name;
$copied = copy($_FILES['image']['tmp_name'], $newname);
if (!$copied)
{
echo '<h1>Copy unsuccessfull!</h1>';
$errors=1;
}}}}

if(isset($_POST['Submit']) && !$errors)
{?>
<img src="<?php echo $newname; ?>" />
<?php echo "<h1>File Uploaded Successfully! Try again!</h1>";
}

?>

<form name="newad" method="post" enctype="multipart/form-data" action="">
<table>
<tr><td><input type="file" name="image"></td></tr>
<tr><td><input name="Submit" type="submit" value="Upload image"></td></tr>
</table>
</form>


</body>
</html>