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array element not being traced by conditional statements but

Posted: Thu Mar 01, 2012 12:34 am
by pbvamsi
I'm not able to trace 'not out' string with conditional statement. Instead it is not being even traced by array search methods. But I can find the element when I print it like

Code: Select all

var_dump($sections[7][5]);
when I try to trace it by conditional statements I fail to extract it. All I wanna do is to return those batsmen name who are not out.

Code: Select all

<?php
ob_start();
$url = 'http://m.cricbuzz.com/cricket-archive/scorecard/10777/1';
$dom = new DOMDocument;
@$dom->loadHTMLFile($url);
$tds = $dom->getElementsByTagName('td');
foreach ($tds as $td) 
{
echo $td->nodeValue, PHP_EOL;
}
$page = ob_get_contents();
ob_end_flush();
$fp = fopen("output.html","w");
fwrite($fp,$page);
fclose($fp);
$pieces = explode("Bowler", file_get_contents('output.html', FILE_IGNORE_NEW_LINES));
$zaq = explode("\n", $pieces[0]);
unset($zaq[0],$zaq[1],$zaq[2],$zaq[3],$zaq[4]);
 for($i=0;$i<count($zaq);$i++)
 {
 if ($zaq[$i]=='') { unset($zaq[$i]); echo 'reached here..  '; }
  } 
foreach($zaq as $value) 
{
echo '<br>the next elemnt is..        '.$value.'<br>';
} 
$sections = array_chunk($zaq, 6);
  var_dump($sections[7][5]);
 echo array_search('not out', $sections);
 print_r(array_values($sections));
 print_r(array_keys($sections)); 
 echo array_key_exists('not out', $search_array);
 for($i=0;$i<count($zaq);$i++)
{
echo $sections[$i][5].'<br>..';
echo count($sections[$i][5]);
$as=count($sections[$i][5]);
if($sections[$i][5]==="'not out") 
{
 echo count($sections[$i][5]);
 echo $sections[$i][5];
 var_dump($sections[$i][5]);
 }
} 
?>
thanks in advance :)

Re: array element not being traced by conditional statements

Posted: Thu Mar 01, 2012 4:14 pm
by social_experiment

Code: Select all

if($sections[$i][5]==="'not out") 
I'm not sure what the output should look like but try removing the ' from the comparison above