Code: Select all
$image = "<img src="../images/checkmark.gif">";
if ($d1 == "y") {
$m1 = '$image; }
echo "$m1";Moderator: General Moderators
Code: Select all
$image = "<img src="../images/checkmark.gif">";
if ($d1 == "y") {
$m1 = '$image; }
echo "$m1";Code: Select all
if ($d1 == "y") {
$m1 = $image;
}Code: Select all
$image = "<img src="../images/checkmark.gif">";
if ($d1 == "y") {
$m1 = '$image'; }Code: Select all
$marked = 'm'.$i; (this properly returns $m1, $m2 etc...)
echo "${$marked}";Code: Select all
if ($d1 == "y") {
$m1 = '$image';
}Code: Select all
if ($d1 == "y") {
$m1 = "$image";
}Code: Select all
$m1 = $image;Code: Select all
$m1 = "$image";heh, you illustrated the point better than I did originally I guess;)twigletmac wrote:You don't need any quotes around variable names by themselves at all:should be used instead of:Code: Select all
$m1 = $image;MacCode: Select all
$m1 = "$image";
Code: Select all
$image = "<img src="../images/checkmark.gif">";
// that is a little confusing, this is a little easier...
$image = '<img src="../images/checkmark.gif">';