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[SOLVED] form to image link
Posted: Sat May 29, 2004 4:22 pm
by nex
Could anyone advise
Is it possible to pass a variable to an image link
<img src="image.php"? <? $quote = $GET_['quote']?> border=0 align=center width=300 height=200></p>
image.php is line chart, so im trying to pass a table name (from a form) to draw the data from.
Posted: Sat May 29, 2004 6:01 pm
by Illusionist
well have you tried it?? It will work, but your syntax is wrong.
try this instead:
<img src="image.php?quote=<?php echo $_GET['quote']; ?>" border=0 align=center width=300 height=200></p>
Posted: Sat May 29, 2004 6:18 pm
by nex
it doesnt work
Do I need to put anything in the image.php to get the 'quote' processed by the script?
Posted: Sat May 29, 2004 8:12 pm
by Illusionist
tog et eh quote in image.php just use:
$_GET['quote']
Posted: Sun May 30, 2004 3:40 am
by nex
tried that didnt work,
Code: Select all
$quote = $_GET['quote'];
$connection = mysql_connect($host,$dbuser,$dbpassword);
if(!$connection)
die("Couldnt connect");
mysql_select_db($database, $connection)
or die("couldnt connect to db".mysql_error());
$res = mysql_query("select* from $quote")
or die("SELECT error".mysql_error());
?>
Posted: Sun May 30, 2004 10:39 am
by Illusionist
ok, what are you trying to do?? wahtever your passing in as quote... do you have a table named that in your database?? And you might want to put a space between select and *
Posted: Sun May 30, 2004 10:39 am
by Illusionist
and are you getting any errors? If so... what are they?
Posted: Sun May 30, 2004 3:18 pm
by nex
I does work now, thanx
syntax error:)