sql problem

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FCB
Forum Newbie
Posts: 8
Joined: Mon Jun 21, 2004 6:12 pm

sql problem

Post by FCB »

i'm strikin out 2night...

Warning: mysql_num_rows(): supplied argument is not a valid MySQL result resource in /home/fleet54/public_html/ezp2/global_fns.php on line 160

Code: Select all

$h1 = mysql_query("select * from '$table' where type = 1");
$q1 = mysql_num_rows($h1);
any help is appreciated
~FCB
d3ad1ysp0rk
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Posts: 1661
Joined: Mon Oct 20, 2003 8:31 pm
Location: Maine, USA

Post by d3ad1ysp0rk »

Is $table set?

Try

Code: Select all

$h1 = mysql_query("select * from {$table} where type = 1");
$q1 = mysql_num_rows($h1);
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feyd
Neighborhood Spidermoddy
Posts: 31559
Joined: Mon Mar 29, 2004 3:24 pm
Location: Bothell, Washington, USA

Post by feyd »

try

Code: Select all

<?php

$h1 = mysql_query("select * from '$table' where type = 1") or die(mysql_error());
$q1 = mysql_num_rows($h1);

?>
I believe 'type' is a reserved word in sql.. It may be complaining about '$table' too.. in which case, you'll need to backtick the names

Code: Select all

<?php

$h1 = mysql_query("select * from `$table` where `type` = 1") or die(mysql_error()); 
$q1 = mysql_num_rows($h1);

?>
FCB
Forum Newbie
Posts: 8
Joined: Mon Jun 21, 2004 6:12 pm

Post by FCB »

augh, i miss-spelled something when i called the function... i hate typing, lol thanks for trying!

~FCB
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