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Posted: Fri Jul 16, 2004 11:31 pm
by John Cartwright
that looks like it will work
but this {} business is going to be used elsewhere on my site...
is there not a way to simply do ${$var}var2;
Posted: Fri Jul 16, 2004 11:46 pm
by feyd
I don't think so.. at least without combining them together partly before hand like:
Code: Select all
<?php
$var = "something";
$somethingvar2 = "wicked";
$something = "jelly";
$jellyvar2 = "juice";
echo ${"{$var}var2"};
?>
Posted: Sat Jul 17, 2004 12:03 am
by John Cartwright
yea thats what i needed

ty feyd lemme try it
edit: wait i see what u mean..
ill let u know on the results
Posted: Sat Jul 17, 2004 12:24 am
by John Cartwright
Code: Select all
<?php
function matchstats($league)
{
//".$config->getcal()."
$cal = mysql_query("SELECT * FROM matches WHERE league='cal-invite'");
while ($record = mysql_fetch_array($cal))
{
switch ($record["outcome"]) :
case "win" :
${"{$league}win"} = ${"{$league}win"} + 1;
break;
case "loss" :
${"{$league}loss"} = ${"{$league}loss"} + 1;
break;
case "tie" :
${"{$league}tie"} = ${"{$league}tie"} + 1;
break;
endswitch;
}
echo ${"{$league}win"};
echo ${"{$league}loss"};
echo ${"{$league}tie"};
}
}
?>
works perfect !!!
ty..:0