array
Posted: Tue Aug 24, 2004 3:38 am
why cannot show the picture using this method?
got another way to do it?
thanks...
got another way to do it?
thanks...
Code: Select all
<?
mysql_select_db($dbname, $link);
$result=mysql_query("select * from user_detail where nickname = '$name'") ;
$number_of_array = mysql_num_rows($result);
while ($number_of_array = mysql_fetch_array($result)){
echo"<img src="./image/$number_of_array[image_name]">";
}
?>