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CHALLENGE _ LIST VALUES ACCORDING TO A DYNAMIC POPULATED COM

Posted: Mon Nov 08, 2004 6:04 am
by rogernem
Hi there. I have a table called menu where there are some menu itens there. I also have a table called "produtos" where I have some products there and their corresponding menu.

MENU
==== ==
$menuitem
Wallpapers
Icons


PRODUTOS
========
$nomeproduto...........$menuitem
Tim...........................Wallpapers
Motorola....................Wallpapers
House........................Icons

Something like that

Well, I have a combo box (dropdown) that is populated according to the itens in the menu table.
What I'd like to do is to list the itens in the table corresponding to that menu item
The way the code is, it just populates the combo but it doesnt show the itens when i change the value of the combo

The code follows bellow:

Code: Select all

<?php 
include ("../toing_conexao.php");
?>
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1">
</head>

<body>
<p align="center"><strong>ADMIN TOING - PRODUTOS : <a href="index.php">Voltar</a> <br>
</strong></p>
<table width="700" border="0" align="center" cellpadding="0" cellspacing="0">
<form action="action_addproditens.php" method="post">
<tr>
<td>* Categoria: </td>
<td>

Code: Select all

<?php
$query="SELECT * FROM menu order by menuitem ASC";
$result=mysql_query($query);
$num=mysql_num_rows($result); 
?>
<select name="menuitem" style="width:200 " onChange="<? $acao ?>">

Code: Select all

<?
$i=0;
while ($i < $num) {
?>
<option>

Code: Select all

<?
$menuitem=mysql_result($result,$i,"menuitem"); 
echo $menuitem;
$i++;
if ($select != 1) {
$acao;
}
}
?>
</option>
</select>
</td>
</tr>

<tr>
<td width="205">* Nome do Produto: </td>
<td width="495"><input name="nomeproduto" type="text" ></td>
</tr>
<tr>
<td>&nbsp;</td>
<td>&nbsp;</td>
</tr>
<tr>
<td colspan="2"><input type="reset" name="Reset" value="Limpar">
<input type="submit" name="Submit2" value="Adicionar"></td>
</tr>
</form>
</table>

<p><strong> Produtos existentes:</strong></p>

Code: Select all

<?
if ( $acao ) {
$sql2="SELECT * FROM produtos WHERE menuitem = '$menuitem' ORDER BY nomeproduto ASC";
$result2=mysql_query($sql2,$conn); 

while ($row = mysql_fetch_array($result2)) {
$id = $row["id_prod"];
$menuitem = $row["menuitem"];
$nomeproduto = $row["nomeproduto"];

echo ("<font face=verdana size=2>- $nomeproduto</font>");
echo "<br>";
}
}
?>
</body>
</html>

If I select "Wallpapers" in the combo I'd like to show in the page:

Produtos existentes:
Tim
Motorola

and if I select "Icons" i'd like to show

Produtos existentes:
House


WHAT SHOUD I DO??
Thank you !!

Posted: Mon Nov 08, 2004 6:31 am
by Weirdan
Moderator's warning
Don't spam the board. One thread is enough.

Posted: Mon Nov 08, 2004 6:35 am
by rogernem
Sorry
It wasnt my intention.