Page 1 of 1
Name a variable after the content of another variable
Posted: Tue Jun 14, 2005 5:13 am
by bokehman
I have a variable named $string. It contains something like abc (letters only). I want a new variable named after its content. eg:
Code: Select all
$string = abc;
//I want a new variable that looks like this:
$abc
Posted: Tue Jun 14, 2005 5:34 am
by shiznatix
use arrays
Code: Select all
$arr = array();
$arr['string'] = 'abc';
$arr[$arr['string']] = 'what you want the $arr[abc] to equal';
Posted: Tue Jun 14, 2005 5:49 am
by onion2k
Err.. use references.
Code: Select all
$string = "abc";
$abc = "hello";
echo $$string; // Note the 2 $ signs.
Posted: Tue Jun 14, 2005 6:33 am
by shiznatix
o wow i never knew you could do that. learn somtin new every day!
Posted: Tue Jun 14, 2005 6:34 am
by timvw
It's a matter of reading the manual

Chapter on variables... Section variable variables
Code: Select all
$name = "tim";
${$name} = "vw";
echo $tim;
Posted: Tue Jun 14, 2005 7:04 am
by Syranide
be careful what you do though, doing such thing on a $_GET-variable could seriously compromise passwords and so on.