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array question
Posted: Tue Jun 14, 2005 5:27 am
by shiznatix
i have a array that looks kinda like this
Code: Select all
[0] => 'cool things here',
[base_skills] => ''
but when i do
Code: Select all
if (isset($array['base_skills']))
{
echo 'cool it worked';
}
it dosn't work but i need it to work so if you could help me make it work that would be terrific
Posted: Tue Jun 14, 2005 6:18 am
by JayBird
works for me
Code: Select all
$array = array(0 => 'cool things here', 'base_skills' => '');
if (isset($array['base_skills'])){
echo 'cool it worked';
}
Posted: Tue Jun 14, 2005 6:29 am
by shiznatix
exactly what i am seeing
print_r($qf_map) outputs this ->
Code: Select all
Array
(
ї1] =>
LEFT JOIN
mdl_cv_personal_info AS person
ON
person.fk_user_id = base.user_id
їbase_skills] =>
)
Code: Select all
if ($qf_map['base_skills'])
{
echo 'worked for me!';
}
//this does not work ^
//this DOES work
if ($qf_map['base_skills'] == '')
{
echo 'worked for me right here!';
}
but it is definatly not working, why?
Posted: Tue Jun 14, 2005 6:41 am
by timvw