Code: Select all
$date1 = "2005-10-20";
$date2 = "2005-9-20"
$daydifference = ($date2 - $date1);
echo "daydifference = 31";Moderator: General Moderators
Code: Select all
$date1 = "2005-10-20";
$date2 = "2005-9-20"
$daydifference = ($date2 - $date1);
echo "daydifference = 31";Code: Select all
<?
$date1 = "20/2/2005"; // dates in d/m/Y format
$date2 = "5/3/2005"; // dates in d/m/Y format
$date1 = explode("/",$date1);
$date2 = explode("/",$date2);
$date1 = date("m/d/Y", strtotime($date1[1]."/".$date1[0]."/".$date1[2]));
$date2 = date("m/d/Y", strtotime($date2[1]."/".$date2[0]."/".$date2[2]));
echo ((strtotime($date2) - strtotime($date1))/86400);
?>Code: Select all
$date1 = "2005-12-20"; // dates in d/m/Y format
$date2 = "2005-12-27"; // dates in d/m/Y format
$date1 = explode("-",$date1);
$date2 = explode("-",$date2);$date1 = date("y-m-d", strtotime($date1[1]."-".$date1[0]."-".$date1[2]));
$date2 = date("y-m-d", strtotime($date2[1]."-".$date2[0]."-".$date2[2]));
echo ((strtotime($date2) - strtotime($date1))/86400);Code: Select all
$date1 = "2005-12-20";
$date2 = "2005-12-27";
echo ((strtotime($date2) - strtotime($date1))/86400);