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Subtracting Dates
Posted: Wed Jul 27, 2005 10:56 am
by polosport6699
I have a simple function that Im sure has a simple solution. I have looked on the php.net website and found some things that are not working. I have two dates. I want to subtract date2 from date1 and calculate the days difference.
Code: Select all
$date1 = "2005-10-20";
$date2 = "2005-9-20"
$daydifference = ($date2 - $date1);
echo "daydifference = 31";
Posted: Wed Jul 27, 2005 11:02 am
by Burrito
search this forum you should...answers you will find
Code: Select all
<?
$date1 = "20/2/2005"; // dates in d/m/Y format
$date2 = "5/3/2005"; // dates in d/m/Y format
$date1 = explode("/",$date1);
$date2 = explode("/",$date2);
$date1 = date("m/d/Y", strtotime($date1[1]."/".$date1[0]."/".$date1[2]));
$date2 = date("m/d/Y", strtotime($date2[1]."/".$date2[0]."/".$date2[2]));
echo ((strtotime($date2) - strtotime($date1))/86400);
?>
from here:
viewtopic.php?t=32137&start=0
Posted: Wed Jul 27, 2005 11:19 am
by polosport6699
Yeah I saw that but my date is formatted differently
my date is 2005-12-20. I tried modifying the code to use that format but it doesnt want to work...
Code: Select all
$date1 = "2005-12-20"; // dates in d/m/Y format
$date2 = "2005-12-27"; // dates in d/m/Y format
$date1 = explode("-",$date1);
$date2 = explode("-",$date2);$date1 = date("y-m-d", strtotime($date1[1]."-".$date1[0]."-".$date1[2]));
$date2 = date("y-m-d", strtotime($date2[1]."-".$date2[0]."-".$date2[2]));
echo ((strtotime($date2) - strtotime($date1))/86400);
Posted: Wed Jul 27, 2005 11:33 am
by Burrito
Code: Select all
$date1 = "2005-12-20";
$date2 = "2005-12-27";
echo ((strtotime($date2) - strtotime($date1))/86400);