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Problems with creating array of associative arrays[SOLVED]

Posted: Thu Nov 03, 2005 6:14 pm
by raghavan20
I don't really know what is the problem with the code below.

Code: Select all

<?php

				$store_array = array();

				$store_array[0] = array("name"=>"MemberId", "value"=>"NULL", "type"= "integer");
				$store_array[1] = array("name"=>"UserName", "value"=>$user_name, "type"=>"string");
				$store_array[2] = array("name"=>"Password", "value"=>$password, "type"= "string");
				$store_array[3] = array("name"=>"FirstName", "value"=>$first_name, "type"= "string");
				$store_array[4] = array("name"=>"LastName", "value"=>$last_name, "type"= "string");
				$store_array[5] = array("name"=>"Email", "value"=>$user_name, "type"= "string");
				$store_array[6] = array("name"=>"Phone", "value"=>$phone, "type"= "string");
				$store_array[7] = array("name"=>"PrivelegeId", "value"=>2, "type"= "integer");
				$store_array[8] = array("name"=>"JoinDate", "value"=>"NOW()", "type"= "integer");
				echo "<br />"; print_r($store_array);

?>
Error reported:

Code: Select all

Parse error: parse error, expecting `')'' in /home/www/letter2india.farvista.net/trial.php on line 5
Any kind of suggestion is welcome.

Re: Problems with creating array of associative arrays

Posted: Thu Nov 03, 2005 6:23 pm
by timvw
raghavan20 wrote:

Code: Select all

$store_array[0] = array("name"=>"MemberId", "value"=>"NULL", "type"= "integer");
A couple of simple typos... missing >

$store_array[0] = array("name"=>"MemberId", "value"=>"NULL", "type"=> "integer");

Posted: Thu Nov 03, 2005 7:18 pm
by raghavan20
Thanks timvw, that solved the problem.