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Preg Match All question
Posted: Sun Feb 12, 2006 1:51 pm
by Shendemiar
Code: Select all
<?
$source= "<a href=\"http://www.xxx.fi/index.php?Menu=Kunnat\" target=\"Paasivu\">\"Kunnat\" osiosta.</a>";
preg_match_all("/<a href(.*?)<\/a>/mi", $source, $matches);
echo var_export($matches,1);
?>
Outputs
Code: Select all
array (
0 =>
array (
0 => '<a href="http://www.xxx.fi/index.php?Menu=Kunnat" target="Paasivu">"Kunnat" osiosta.</a>',
),
1 =>
array (
0 => '="http://www.xxx.fi/index.php?Menu=Kunnat" target="Paasivu">"Kunnat" osiosta.',
),
)
How come it gives two matches?
Posted: Sun Feb 12, 2006 2:18 pm
by feyd
your usage of parenthesis.
Posted: Sun Feb 12, 2006 4:21 pm
by josh
To elaborate, the first match is the entire string that was matched, the second one is the extracted piece of the string that matched the part in parenthesis
Posted: Sun Feb 12, 2006 5:10 pm
by Shendemiar
jshpro2 wrote:To elaborate, the first match is the entire string that was matched, the second one is the extracted piece of the string that matched the part in parenthesis
First i was like WTF, but thats actually quite usefull...