Problem returing Array
Posted: Tue May 30, 2006 8:13 am
feyd | Please use
Function code:
Doing a trace, the function is called and executed OK. When showing the "echo" before returning the Array I can see that the variable $datos has data.
Could anyone help?
Thanks.
feyd | Please use
Code: Select all
,Code: Select all
and [syntax="..."] tags where appropriate when posting code. Your post has been edited to reflect how we'd like it posted. Please read: [url=http://forums.devnetwork.net/viewtopic.php?t=21171]Posting Code in the Forums[/url] to learn how to do it too.[/color]
Hi,
I have developed a program that works with PHP 4 and when I tried to move it to a new site with PHP 5.0.5 is failing.
When calling to the function "ejecutarsql" the array is not returned, but the rows are detected.Code: Select all
$query = "SELECT * FROM " . BD_TABLE . " $where ORDER BY Nombre $limit";
$rows = $bd -> ejecutarsql( $query );
if( $bd -> filas_resultantes( ) ) {
reset( $rows );
foreach ( $rows as $r ) {
}Code: Select all
function ejecutarsql( $instruccion, $num_rows = 0, $offset = 0 ) {
$conn = $this -> db_conn;
$resultado = false;
for ( $i = 0; $i < NUM_REINTENTOS_EN_BLOQUEOS; $i++ ) {
if ( $num_rows != 0 ) {
$resultado = $conn -> SelectLimit( $instruccion, $num_rows, $offset );
} else {
$resultado = $conn -> Execute( $instruccion );
}
if ( $resultado != false ) {
for ( $j = 0; $j < $resultado -> RecordCount(); $j++ ) {
$aux[ $j ] = $resultado -> GetArray();
$resultado -> NextRecordSet();
$datos[ $j ] = $aux[ 0 ][ $j ];
}
$this -> error = NO_ERROR;
$this -> resultado = $resultado;
echo "resultado".$datos;
return $datos;
} else {
continue;
}
}
$this -> error = ERR_BLOQUEO;
return false;
}Could anyone help?
Thanks.
feyd | Please use
Code: Select all
,Code: Select all
and [syntax="..."] tags where appropriate when posting code. Your post has been edited to reflect how we'd like it posted. Please read: [url=http://forums.devnetwork.net/viewtopic.php?t=21171]Posting Code in the Forums[/url] to learn how to do it too.[/color]