Notice: Undefined index:
Posted: Sun Dec 15, 2002 12:51 pm
I dont know if I posted this here before or not, but everybody that tried to help me on it, nothing seemed to work,,, Its driving me crazy
Im developing a script and i have a couple of Notice's:
----------------------------------------------------------------------
1.)
Notice: Undefined index: admin in index.php on line 34
2.)
Notice: Undefined index: featured in index.php on line 435
---------------------------------------------------------------------
I was told there is a way to get rid of these notice's in my code, without going into php.ini and hideing the notice's..
for the first notice (1)
----------------------------------------------------------------------
for a login, im using a cookie to keep the administrator logged in,,,
if ($_POST["user"] == $login && $_POST["password"] == $pass) {
setcookie("admin", "loggedin", "+3600");
header('Location: index.php');
}
it is called after the administrator logs in, then it will open the rest of the code..
if($_COOKIE['admin'] == "loggedin"){
(code here)
}
Now, i get the Notice before the user logs in on the login page,,, the login page is called be the else statement after the $cookie login...
else{
login page
}
so the variable is not = to anything at the time,,,
i was told to use issett() to fix that, but when i do, it dont work at all..
it just shows the login page over again,,
and dont login..
is there a way i can fix this?
----------------------------------------------------------------------
for the seconde notice (2):
----------------------------------------------------------------------
the seconde notice is just passing a variable with a check box,,, to another page...
here is the code i use for the check box:
if($_REQUEST["featured2"] == "yes") {
echo "<font color=red><B>Featured!<input name=featured type=hidden value=yes>";
}
else{
echo "Make Featured ? <input name=featured type=checkbox value=yes>";
}
the else statement is the part that shows up on page, and if the check box is not checked, then the value would be no, but i dont know how i can pass the variable featured=no to the next page with this check box,,, so on the next page i get the 2nd notice....
because im trying to call a variable that does equal anything,,,
ive even made an if statment on the next page to try to fix this,,, and it does work,,,
if($_REQUEST["featured"] == ""){
$_REQUEST["featured"] = "no";
}
ive even used;
if($_REQUEST["featured"] == 0){
$_REQUEST["featured"] = "no";
}
and it still gives me the same notice...
If there was a way to take the code from the check box like this:
<input name=featured type=hidden
<?
if($checked){
echo "value=yes>";
}
esle{
echo "value=no>";
}
would be so great,,,but we both no that wont work,, but its an example that i can only come up with...
any suggestions?
Im developing a script and i have a couple of Notice's:
----------------------------------------------------------------------
1.)
Notice: Undefined index: admin in index.php on line 34
2.)
Notice: Undefined index: featured in index.php on line 435
---------------------------------------------------------------------
I was told there is a way to get rid of these notice's in my code, without going into php.ini and hideing the notice's..
for the first notice (1)
----------------------------------------------------------------------
for a login, im using a cookie to keep the administrator logged in,,,
if ($_POST["user"] == $login && $_POST["password"] == $pass) {
setcookie("admin", "loggedin", "+3600");
header('Location: index.php');
}
it is called after the administrator logs in, then it will open the rest of the code..
if($_COOKIE['admin'] == "loggedin"){
(code here)
}
Now, i get the Notice before the user logs in on the login page,,, the login page is called be the else statement after the $cookie login...
else{
login page
}
so the variable is not = to anything at the time,,,
i was told to use issett() to fix that, but when i do, it dont work at all..
it just shows the login page over again,,
and dont login..
is there a way i can fix this?
----------------------------------------------------------------------
for the seconde notice (2):
----------------------------------------------------------------------
the seconde notice is just passing a variable with a check box,,, to another page...
here is the code i use for the check box:
if($_REQUEST["featured2"] == "yes") {
echo "<font color=red><B>Featured!<input name=featured type=hidden value=yes>";
}
else{
echo "Make Featured ? <input name=featured type=checkbox value=yes>";
}
the else statement is the part that shows up on page, and if the check box is not checked, then the value would be no, but i dont know how i can pass the variable featured=no to the next page with this check box,,, so on the next page i get the 2nd notice....
because im trying to call a variable that does equal anything,,,
ive even made an if statment on the next page to try to fix this,,, and it does work,,,
if($_REQUEST["featured"] == ""){
$_REQUEST["featured"] = "no";
}
ive even used;
if($_REQUEST["featured"] == 0){
$_REQUEST["featured"] = "no";
}
and it still gives me the same notice...
If there was a way to take the code from the check box like this:
<input name=featured type=hidden
<?
if($checked){
echo "value=yes>";
}
esle{
echo "value=no>";
}
would be so great,,,but we both no that wont work,, but its an example that i can only come up with...
any suggestions?