problem with simple login script
Posted: Fri Aug 18, 2006 11:56 am
feyd | Please use
I have the above code, and whenever I try to submit the form, it displays this in the address bar:
http://www.subaddress.myaddress.co.uk/i ... ssientered.
This puzzles me because 1. I am not sending the form to index.php, and 2. I am using POST, therefore the data should not be able to be observed in the address bar.
Hope somebody can help,, its driving me mad!
feyd | Please use
Code: Select all
,Code: Select all
and [syntax="..."] tags where appropriate when posting code. Your post has been edited to reflect how we'd like it posted. Please read: [url=http://forums.devnetwork.net/viewtopic.php?t=21171]Posting Code in the Forums[/url] to learn how to do it too.[/color]Code: Select all
<?php
include("include-mysql.php");
if(!isset($_SESSION['myusername'])) {
?>
<form action="check_login.php"
method="post">
<table align="center" bgcolor="#CCCCCC">
<tr>
<td align="right">Username: </td>
<td><input type="text" name="myusername" id="myusername"></td>
</tr>
<tr>
<td width="92" align="right">Password: </td>
<td width="189"><input type="password" name="mypassword" id="mypassword"></td>
</tr>
<tr>
<td colspan="2" align="center"><input type="submit" value="Log in" /></td>
</tr>
</table>
</form>
<?php
//exit;
} else {
echo 'You are already logged in.';
}
?>http://www.subaddress.myaddress.co.uk/i ... ssientered.
This puzzles me because 1. I am not sending the form to index.php, and 2. I am using POST, therefore the data should not be able to be observed in the address bar.
Hope somebody can help,, its driving me mad!
feyd | Please use
Code: Select all
,Code: Select all
and [syntax="..."] tags where appropriate when posting code. Your post has been edited to reflect how we'd like it posted. Please read: [url=http://forums.devnetwork.net/viewtopic.php?t=21171]Posting Code in the Forums[/url] to learn how to do it too.[/color]