feyd | Please use Code: Select all
and [syntax="..."] tags where appropriate when posting code. Your post has been edited to reflect how we'd like it posted. Please read: [url=http://forums.devnetwork.net/viewtopic.php?t=21171]Posting Code in the Forums[/url] to learn how to do it too.[/color]
This is my code of the first page it contains javascript function to add or delete items from one listbox to another,listbox named select1 is populated from database(put garbage value if you want to check), and when done the generate report button send this whole values from listbox named select2 to the next page in form of querystring which shows like:
Code: Select all
http://localhost/final/junk2.php?select2=ActivityMonitor1&select2=ActivityMonitor2&select2=ActivityMonitor6&select2=adfasf&select2=002&genRep=Generate+Report
, now what I want is that these values should be stored into an array or something because I have some other works to do with them, let see how you handle this now,banking on your brilliance:
Code: Select all
<html>
<body>
<script language="JavaScript">
function deleteOption(object,index)
{
object.options[index] = null;
}
function addOption(object,text,value)
{
var defaultSelected = true;
var selected = true;
var optionName = new Option(text, value, defaultSelected, selected)
object.options[object.length] = optionName;
}
function copySelected(fromObject,toObject)
{
for (var i=0, l=fromObject.options.length;i<l;i++)
{
if (fromObject.options[i].selected)
addOption(toObject,fromObject.options[i].text,fromObject.options[i].value);
}
for (var i=fromObject.options.length-1;i>-1;i--)
{
if (fromObject.options[i].selected)
deleteOption(fromObject,i);
}
}
function copyAll(fromObject,toObject)
{
for (var i=0, l=fromObject.options.length;i<l;i++)
{
addOption(toObject,fromObject.options[i].text,fromObject.options[i].value);
}
for (var i=fromObject.options.length-1;i>-1;i--)
{
deleteOption(fromObject,i);
}
}
</script>
<form name=form1 action="junk2.php">
<p align="center">
<select name="select1" multiple size="5">
<?php
include ("include/database.php");
$link = mysql_connect($dbServer, $dbUser, $dbPassword);
if (!$link)
{
die('Could not connect: ' . mysql_error());
}
else
{
mysql_select_db('project');
$result = mysql_query("SELECT projCode FROM defineproject WHERE projStatus = 'active'");
while ( $query_data = mysql_fetch_array($result))
{
?>
<option value= <? echo @$query_data["projCode"]; ?>>
<?
echo $query_data["projCode"];
}
mysql_free_result($result);
}
mysql_close( $link );
?>
</option>
</select>
</p>
<p align="center">
<input type="button" value=" > " onClick="if (document.images) copySelected(this.form.select1,this.form.select2)">
<p align="center">
<input type="button" value=" < " onClick="if (document.images) copySelected(this.form.select2,this.form.select1)">
<p align="center">
<input type="button" value=">>" onClick="if (document.images) copyAll(this.form.select1,this.form.select2)">
<p align="center">
<input type="button" value="<<" onClick="if (document.images) copyAll(this.form.select2,this.form.select1)">
<p align="center">
<select name="select2" multiple size="5">
</select>
</p>
<p align="center"><font face="Verdana">
<input type="submit" value="Generate Report" name="genRep" style="font-family: Verdana" >
</font></p>
</form>
</body>
</html>
feyd | Please use Code: Select all
and [syntax="..."] tags where appropriate when posting code. Your post has been edited to reflect how we'd like it posted. Please read: [url=http://forums.devnetwork.net/viewtopic.php?t=21171]Posting Code in the Forums[/url] to learn how to do it too.[/color]