CURL question
Posted: Mon Dec 11, 2006 9:59 am
Hi,
I'm trying to use cURL to get the contents of a website.
I'm testing an example provided by godaddy (my host). Now for some reason it seems to work with every URL I've tested it with, except one (unfortunately, the one I need): http://www.whl.ca/hm/ <With this webpage all I get is a blank page (a timeout error I think).
Every other URL I have tested works justs fine.
Here's the code:
Any help would be greatly appreciated...and sorry for my poor English.
I'm trying to use cURL to get the contents of a website.
I'm testing an example provided by godaddy (my host). Now for some reason it seems to work with every URL I've tested it with, except one (unfortunately, the one I need): http://www.whl.ca/hm/ <With this webpage all I get is a blank page (a timeout error I think).
Every other URL I have tested works justs fine.
Here's the code:
Code: Select all
<?
$URL="https://www.paypal.com";
if (isset($_GET["site"])) { $URL = $_GET["site"]; }
$ch = curl_init();
echo "URL = $URL <br>\n";
curl_setopt($ch, CURLOPT_VERBOSE, 1);
//curl_setopt ($ch, CURLOPT_HTTPPROXYTUNNEL, TRUE);
curl_setopt ($ch, CURLOPT_PROXYTYPE, CURLPROXY_HTTP);
curl_setopt ($ch, CURLOPT_PROXY,"http://proxy.shr.secureserver.net:3128");
curl_setopt ($ch, CURLOPT_SSL_VERIFYPEER, FALSE);
curl_setopt ($ch, CURLOPT_URL, $URL);
curl_setopt ($ch, CURLOPT_TIMEOUT, 120);
$result = curl_exec ($ch);
echo "<hr><br>\n";
echo 'Errors: ' . curl_errno($ch) . ' ' . curl_error($ch) . '<br><br>';
echo "<hr><br>\n";
curl_close ($ch);
print "result - $result";
echo "<hr><br>\n";
?>