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and [syntax="..."] tags where appropriate when posting code. Your post has been edited to reflect how we'd like it posted. Please read: [url=http://forums.devnetwork.net/viewtopic.php?t=21171]Posting Code in the Forums[/url] to learn how to do it too.[/color]
I am fairly new to PHP. I am taking a Java course, and alot of PHP seems similar to Java.
I would like to make a include command which includes the name of the file at the end of the page, for example
if the user goes to index.php?goto=downloads.php
it calls for downloads.php.
So far i have this much:Code: Select all
<?php
$path_parts = pathinfo('/www/htdocs/index.txt');
echo $path_parts['dirname'], "\n";
echo $path_parts['basename'], "\n";
echo $path_parts['extension'], "\n";
echo $path_parts['filename'], "\n"; // since PHP 5.2.0
?>
<?php include($path_parts['basename'])?>I'm guessing you'd have to put in the parenthesis of the pathinfo the function, but im not sure how to do that. Any help is greatly appreciated.
feyd | Please use
Code: Select all
,Code: Select all
and [syntax="..."] tags where appropriate when posting code. Your post has been edited to reflect how we'd like it posted. Please read: [url=http://forums.devnetwork.net/viewtopic.php?t=21171]Posting Code in the Forums[/url] to learn how to do it too.[/color]