$query_albumcheck = "SELECT * FROM albums WHERE owner = '$_COOKIE[email]' & name = '$_POST[albumname]'";
Help with a PHP and mySql question.
Moderator: General Moderators
Help with a PHP and mySql question.
I am trying to search the ALBUMS database to see if there is already and album with the same name with the current logged in user. Why wont this work? sorry such an amateur question. Im learning
All help appreciated.
$query_albumcheck = "SELECT * FROM albums WHERE owner = '$_COOKIE[email]' & name = '$_POST[albumname]'";
$query_albumcheck = "SELECT * FROM albums WHERE owner = '$_COOKIE[email]' & name = '$_POST[albumname]'";
try Does $query_albumcheck contain what you expect?
Code: Select all
$query_albumcheck = "SELECT * FROM albums WHERE owner = '$_COOKIE[email]' & name = '$_POST[albumname]'";
echo '<div>Debug: ', htmlentities($query_albumcheck), "</div>\n";-
renatopedigoni
- Forum Newbie
- Posts: 1
- Joined: Sun Jul 08, 2007 4:02 pm
- Location: franca, sp, brazil
Re: Help with a PHP and mySql question.
trybos45430 wrote:$query_albumcheck = "SELECT * FROM albums WHERE owner = '$_COOKIE[email]' & name = '$_POST[albumname]'";
Code: Select all
$query_albumcheck = "SELECT * FROM albums WHERE owner = '".$_COOKIE['email']."' AND name = '".$_POST['albumname']."'";