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gregTelevirtual
Forum Newbie
Posts: 3 Joined: Thu Jul 12, 2007 6:35 am
Post
by gregTelevirtual » Thu Jul 12, 2007 7:06 am
Hi,
I'm relatively new to php been doing it a couple of weeks and i have a what i think is a basic question. Here is my code.
Code: Select all
<?php
$max = $_POST["max"];
$newArray = array();
$print = FALSE;
for($i=0;$i<$max;$i++)
{
$originalArray[i] = $_POST["text$i"];
if($i == $max - 3 && $print == FALSE)
{
$newArray[0] = $originalArray[i];
//echo " $newArray[0] <br>";
}
if($i == $max - 2 && $print == FALSE)
{
$newArray[1] = $originalArray[i];
//echo " $newArray[1] <br>";
}
if($i == $max - 1 && $print == FALSE)
{
$newArray[2] = $originalArray[i];
//echo " $newArray[2] <br>";
$print = TRUE;
$i = 0;
}
if($i < $max - 3 && $print == FALSE)
{
for($k=$i+3;$k<$i+4;$k++)
{
$newArray[k]=$originalArray[i];
//echo " $newArray[k] ";
}
}
/*why doesn't this loop know what's inside newArray is when it is declared and assigned above*/
if($print == TRUE)
{
echo "$i = $newArray[i]";
if((($i+1) % 3) == 0)
{
echo "<br>";
}
}
}
?>
and the output is
Code: Select all
0 = 1 = 2 =
3 = 4 = 5 =
6 = 7 = 8 =
9 = 10 = 11 =
12 = 13 = 14 =
15 = 16 = 17 =
18 = 19 = 20 =
21 = 22 = 23 =
24 = 25 = 26 =
why doesnt the last loop know what's inside $newArray[] is when it is declared and assigned above.
thanks
Greg
feyd
Neighborhood Spidermoddy
Posts: 31559 Joined: Mon Mar 29, 2004 3:24 pm
Location: Bothell, Washington, USA
Post
by feyd » Thu Jul 12, 2007 7:26 am
Your indices "i" and "k" aren't variables.
Make sure your error_reporting setting is E_ALL instead of E_ALL ^ E_NOTICE (or similar variants.)
gregTelevirtual
Forum Newbie
Posts: 3 Joined: Thu Jul 12, 2007 6:35 am
Post
by gregTelevirtual » Thu Jul 12, 2007 8:52 am
Thanks for the reply
i and k are variables, the code runs which suggests that syntactically it's correct?
The error settings are already E_ALL.
RobertGonzalez
Site Administrator
Posts: 14293 Joined: Tue Sep 09, 2003 6:04 pm
Location: Fremont, CA, USA
Post
by RobertGonzalez » Thu Jul 12, 2007 10:42 am
The way the code is now 'i' and 'k' are constants, not variables. Look closely at them and see if you can spot why PHP would assume they are constants.
gregTelevirtual
Forum Newbie
Posts: 3 Joined: Thu Jul 12, 2007 6:35 am
Post
by gregTelevirtual » Thu Jul 12, 2007 10:53 am
thank you!
I got it.
all the arrays should be assigned like this
$originalArray[$i] NOT $originalArray
it works now.
cheers
Greg