Problem with search engine.

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valters
Forum Newbie
Posts: 4
Joined: Tue Jul 24, 2007 5:26 am

Problem with search engine.

Post by valters »

feyd | Please use

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,

Code: Select all

and [syntax="..."] tags where appropriate when posting code. Your post has been edited to reflect how we'd like it posted. Please read:  [url=http://forums.devnetwork.net/viewtopic.php?t=21171]Posting Code in the Forums[/url] to learn how to do it too.[/color]


When i need to add search engine to my page, i have discovered one problem, but i cant get answer, because all code are fine, but i have error - Couldn't execute query

Code: Select all

<?

  // Get the search variable from URL

  $var = @$_POST['q'];
  $trimmed = trim($var); //trim whitespace from the stored variable

// rows to return
$limit=10;

// check for an empty string and display a message.
if ($trimmed == "")
  {
  echo "<p>Please enter a search...</p>";
  exit;
  }

// check for a search parameter
if (!isset($var))
  {
  echo "<p>We dont seem to have a search parameter!</p>";
  exit;
  }

//connect to your database ** EDIT REQUIRED HERE **
mysql_connect("localhost", "user", "password");
mysql_select_db("database") or die("Unable to select database"); //select which database we're using

// Build SQL Query  
$query = "SELECT * FROM tables WHERE field_1 like \"%$trimmed%\" OR field_2 like \"%$trimmed%\"
  order by field_1"; // EDIT HERE and specify your table and field names for the SQL query

$numresults=mysql_query($query);
$numrows=mysql_num_rows($numresults);

// If we have no results, offer a google search as an alternative

if ($numrows == 0)
  {
  echo "<h4>Results</h4>";
  echo "<p>Sorry, your search: "" . $trimmed . "" returned zero results</p>";

// google
echo "<p><a href=\"http://www.google.com/search?q="
  . $trimmed . "\" target=\"_blank\" title=\"Look up
  " . $trimmed . " on Google\">Click here</a> to try the
  search on google</p>";
  }

// next determine if s has been passed to script, if not use 0
  if (empty($s)) {
  $s=0;
  }

// get results
  $query .= " limit $s,$limit";
  $result = mysql_query($query) or die("Couldn't execute query");

// display what the person searched for
echo "<p>You searched for: "" . $var . ""</p>";

// begin to show results set
echo "Results";
$count = 1 + $s;

// now you can display the results returned
  while ($row= mysql_fetch_array($result)) {
  $title = $row["1st_field"];

  echo "$count.)&nbsp;$title";
  $count++;
  }

$currPage = (($s/$limit) + 1);

//break before paging
  echo "<br />";

  // next we need to do the links to other results
  if ($s>=1) { // bypass PREV link if s is 0
  $prevs=($s-$limit);
  print "&nbsp;<a href=\"$PHP_SELF?s=$prevs&q=$var\"><<
  Prev 10</a>&nbsp&nbsp;";
  }

// calculate number of pages needing links
  $pages=intval($numrows/$limit);

// $pages now contains int of pages needed unless there is a remainder from division

  if ($numrows%$limit) {
  // has remainder so add one page
  $pages++;
  }

// check to see if last page
  if (!((($s+$limit)/$limit)==$pages) && $pages!=1) {

  // not last page so give NEXT link
  $news=$s+$limit;

  echo "&nbsp;<a href=\"$PHP_SELF?s=$news&q=$var\">Next 10 >></a>";
  }

$a = $s + ($limit);
  if ($a > $numrows) { $a = $numrows; }
  $b = $s + 1;
  echo "<p>Showing results $b to $a of $numrows</p>";
  
?>

feyd | Please use

Code: Select all

,

Code: Select all

and [syntax="..."] tags where appropriate when posting code. Your post has been edited to reflect how we'd like it posted. Please read:  [url=http://forums.devnetwork.net/viewtopic.php?t=21171]Posting Code in the Forums[/url] to learn how to do it too.[/color]
User avatar
dude81
Forum Regular
Posts: 509
Joined: Mon Aug 29, 2005 6:26 am
Location: Pearls City

Post by dude81 »

I suggest you to print the query and see and execute the same on mysql database
miro_igov
Forum Contributor
Posts: 485
Joined: Fri Mar 31, 2006 5:06 am
Location: Bulgaria

Post by miro_igov »

What is the problem? Are you sure you should compare the field_1 and field_2 separately to the entered search?
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