Code: Select all
<script type='text/javascript'>
document.write(photo[0])
</script>Code: Select all
$image="$dir/$java";This is creating the source for the image. And of course it outputs the full javascript code instead of printing the array when it is called upon in $image.
My question is how do I get the array name to show instead of the javascript code? I'm thinking it must be done with a function() . . .
This is how I'm using it:
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//Gets the width and height of the image and outputs it
$theimage = getimagesize($image);
$width = $theimage[0];
$height = $theimage[1];document.write(photo[0])
</script>
as oppose to (what I want) http://website.com/images/photo1.jpg