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ashrafzia
Forum Commoner
Posts: 37 Joined: Wed Sep 28, 2005 12:23 pm
Post
by ashrafzia » Mon Oct 22, 2007 9:07 am
I want the value of the variable $user to go inside the if statement inside the query, but its not working.
How can i make the value of the variable $user as a global for access inside if....else block statements.
Code: Select all
$val = $_GET['id'];
$user = $_GET['user'];
if ($val == "AddPaper" && !isset($_POST['next_x'])){
//echo "$user";
$sql="SELECT programe_name FROM teachers WHERE teacher_name='$user' ";
$result = mysql_query($sql, $conn) or die ("Can't Process Query".mysql_query());
while ($row=mysql_fetch_array($result)){
$add1 .= "<option value='$row[programe_name]'>$row[programe_name]</option>";
}
I have a dropdown menu which has a link as
http://localhost/xampp/......../myfile?id=AddPaper
when i click the button the above if statement is executed but the value of the variable $user isn't coming inside it and before the button click i have a value inside the link as
http://localhost/xampp.......myfile?user=$_post[name ].
I hope you get what i want to say.
aaronhall
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Posts: 1040 Joined: Tue Aug 13, 2002 5:10 pm
Location: Back in Phoenix, missing the microbrews
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Post
by aaronhall » Mon Oct 22, 2007 9:09 am
if blocks don't maintain their own scope like functions do. $user will be visible inside that block. Check that the if conditions are evaluating to true.
ashrafzia
Forum Commoner
Posts: 37 Joined: Wed Sep 28, 2005 12:23 pm
Post
by ashrafzia » Mon Oct 22, 2007 9:14 am
aaronhall wrote: if blocks don't maintain their own scope like functions do. $user will be visible inside that block. Check that the if conditions are evaluating to true.
I have checked the if condition are evaluating to true but the value of the variable isn't printing.
I have echoed it. Above if statement its working, but inside if statement its not working.
aaronhall
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Posts: 1040 Joined: Tue Aug 13, 2002 5:10 pm
Location: Back in Phoenix, missing the microbrews
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Post
by aaronhall » Mon Oct 22, 2007 9:44 am
Place this line directly above the if statement:
Code: Select all
var_dump($val == "AddPaper" && !isset($_POST['next_x']);
If it doesn't print true, the statement isn't true
ashrafzia
Forum Commoner
Posts: 37 Joined: Wed Sep 28, 2005 12:23 pm
Post
by ashrafzia » Mon Oct 22, 2007 12:46 pm
aaronhall wrote: Place this line directly above the if statement:
Code: Select all
var_dump($val == "AddPaper" && !isset($_POST['next_x']);
If it doesn't print true, the statement isn't true
It's giving a parse error and will you kindly explain what is it used for ?
John Cartwright
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Posts: 11470 Joined: Tue Dec 23, 2003 2:10 am
Location: Toronto
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Post
by John Cartwright » Mon Oct 22, 2007 1:06 pm
ashrafzia wrote: aaronhall wrote: Place this line directly above the if statement:
Code: Select all
var_dump($val == "AddPaper" && !isset($_POST['next_x']);
If it doesn't print true, the statement isn't true
It's giving a parse error and will you kindly explain what is it used for ?
It's missing a closing bracket.
Try var_dump()'ing all the variables separately to get a better picture.
Code: Select all
echo 'Val: '; var_dump($val); echo '<br />';
echo '$_POST[\'next_x\']: '; var_dump($_POST['next_x']); echo '<br />';
echo 'if(): '; var_dump($val == "AddPaper" && !isset($_POST['next_x']));
ashrafzia
Forum Commoner
Posts: 37 Joined: Wed Sep 28, 2005 12:23 pm
Post
by ashrafzia » Mon Oct 22, 2007 1:24 pm
Jcart wrote:
It's missing a closing bracket.
Try var_dump()'ing all the variables separately to get a better picture.
Code: Select all
echo 'Val: '; var_dump($val); echo '<br />';
echo '$_POST[\'next_x\']: '; var_dump($_POST['next_x']); echo '<br />';
echo 'if(): '; var_dump($val == "AddPaper" && !isset($_POST['next_x']));
Its giving the following output:
Code: Select all
Val: NULL
$_POST['next_x']: NULL
if(): bool(false)