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statement foreach ... help!!
Posted: Mon Apr 07, 2003 4:22 am
by valentik
Excuse for my English, I am Italian and I try to learn PHP.
You would know me what does not go in this
$a[0][0] = "a";
$a[0][1] = "b";
$a[1][0] = "y";
$a[1][1] = "z";
foreach($a as $v1) {
foreach ($v1 as $v2) { // line 42
print "$v2\n";
}
}
Warning: Invalid argument supplied for foreach() in /usr/local/apache2/htdocs/test/foreach.php on line 42
Posted: Mon Apr 07, 2003 4:30 am
by d1223m
oh i see its actually an example from the manual

Posted: Mon Apr 07, 2003 4:33 am
by twigletmac
That's strange, I ran your code and it works fine for me. Perhaps something else in your code is not working as expected, for debugging try:
Code: Select all
$a[0][0] = "a";
$a[0][1] = "b";
$a[1][0] = "y";
$a[1][1] = "z";
echo '<pre>$a contains: ';
print_r($a);
echo '</pre>';
foreach($a as $v1) {
echo '<pre>$v1 contains: ';
print_r($v1);
echo '</pre>';
foreach ($v1 as $v2) { // line 42
print "$v2\n";
}
}
You should get output that looks like:
Code: Select all
$a contains: Array
(
ї0] => Array
(
ї0] => a
ї1] => b
)
ї1] => Array
(
ї0] => y
ї1] => z
)
)
$v1 contains: Array
(
ї0] => a
ї1] => b
)
a b
$v1 contains: Array
(
ї0] => y
ї1] => z
)
y z
Mac
Posted: Mon Apr 07, 2003 4:35 am
by twigletmac
d1223m wrote:oh i see its actually an example from the manual

valentik - are you using the code 'as is' or did you modify it? If so could we see any modifications you made to it.
Mac
Posted: Mon Apr 07, 2003 4:52 am
by d1223m
im wondering if you have an old version of php maybe?
Posted: Mon Apr 07, 2003 5:23 am
by d1223m
ok - its not your version