Hi all
My issue is
I am taking images from a server with names like, img1,img2,img3 etc..(Not from the database)
If there are more than 5 images, i need pagination.
currently using a loop it is displayed..all the images..like
for($i=0;$i<cnt;$i++)
<img src="http://otherserver...../img$i.jpg">
But i need to use pagination for this..
How to make this..pls help
Regarding Pagination(Not using database)
Moderator: General Moderators
Re: Regarding Pagination(Not using database)
You do it in exactly the same way as any other paging system. The fact there's a database involved or not doesn't change anything. At it's most basic you'd do something like ...
Obviously that code is pretty incomplete (and completely untested) ... it'll break if someone sets $_GET['page'] to -1 for example. The point is that you need to start the loop that displays the images at $page*$records_per_page, and stop it at ($page+1)*$records_per_page. The rest is easy.
Code: Select all
$total_number_of_images = 100;
$records_per_page = 5;
$total_number_of_pages = floor($total_number_of_images/$records_per_page);
$current_page = (!empty($_GET['page'])) ? intval($_GET['page']) : 0;
for($i=($current_page*$records_per_page);$i<(($current_page+1)*$records_per_page);$i++) {
echo "<img src=\"img".$i.".jpg\">";
}
for ($p=0; $p<$total_number_of_pages; $p++) {
echo "<a href=\"gallery.php?page=".$p."\">Page ".$p."</a>";
}