login/logout question
Posted: Mon Apr 28, 2003 9:12 am
at present i have the following script
<?
if ($userid && $password)
{
// if the user has just tried to log in
$db_conn = mysql_connect("localhost", "cadmin", "cpass");
mysql_select_db("crimson", $db_conn);
$query = "select * from user "
."where username='$userid' "
." and passwd='$password' ";
$result = mysql_query($query, $db_conn);
if (mysql_num_rows($result) >0 )
{
// if they are in the database register the user id
$valid_user = $userid;
session_register("valid_user");
}
}
if (session_is_registered("valid_user"))
{
echo "You are logged in as: $valid_user <br>";
echo "<a href=\"index.php?page=logout\">Log out</a><br>";
}
else
{
if (isset($userid))
{
// if they've tried and failed to log in
echo "Could not log you in";
}
else
{
// they have not tried to log in yet or have logged out
echo "<div class=\"log\">You are not logged in.</div>";
}
// provide form to log in
echo "<form method=post action=\"index.php?page=authmain\">";
echo "<table class=\"log\">";
echo "<td>Userid:</td>";
echo "<td><input type=text name=userid></td>";
echo "<td>Password:</td>";
echo "<td><input type=password name=password></td>";
echo "<td colspan=2 align=center>";
echo "<input type=submit value=\"Log in\"></td></tr>";
echo "</table></form>";
}
?>
and this as logout
<?
$old_user = $valid_user; //test if user *were* logged in
$result = session_unregister("valid_user");
session_destroy();
?>
Log out
<?
if (!empty($old_user))
{
if ($result)
{
// if user was logged in and are not logged out
echo "You are now logged out.";
}
else
{
// user was logged in and could not be logged out
echo "Could not log you out.";
}
}
else
{
// not logged in and accessed this page
echo "You were not logged in.";
}
?>
I'm trying to make it so when you click log out the text saying you are logged in is replaced with "you are logged out"
at the moment the text pops up saying your logged out but the other text saying your logged in is still there.
site is http://www.irealms.co.uk/crimson
<?
if ($userid && $password)
{
// if the user has just tried to log in
$db_conn = mysql_connect("localhost", "cadmin", "cpass");
mysql_select_db("crimson", $db_conn);
$query = "select * from user "
."where username='$userid' "
." and passwd='$password' ";
$result = mysql_query($query, $db_conn);
if (mysql_num_rows($result) >0 )
{
// if they are in the database register the user id
$valid_user = $userid;
session_register("valid_user");
}
}
if (session_is_registered("valid_user"))
{
echo "You are logged in as: $valid_user <br>";
echo "<a href=\"index.php?page=logout\">Log out</a><br>";
}
else
{
if (isset($userid))
{
// if they've tried and failed to log in
echo "Could not log you in";
}
else
{
// they have not tried to log in yet or have logged out
echo "<div class=\"log\">You are not logged in.</div>";
}
// provide form to log in
echo "<form method=post action=\"index.php?page=authmain\">";
echo "<table class=\"log\">";
echo "<td>Userid:</td>";
echo "<td><input type=text name=userid></td>";
echo "<td>Password:</td>";
echo "<td><input type=password name=password></td>";
echo "<td colspan=2 align=center>";
echo "<input type=submit value=\"Log in\"></td></tr>";
echo "</table></form>";
}
?>
and this as logout
<?
$old_user = $valid_user; //test if user *were* logged in
$result = session_unregister("valid_user");
session_destroy();
?>
Log out
<?
if (!empty($old_user))
{
if ($result)
{
// if user was logged in and are not logged out
echo "You are now logged out.";
}
else
{
// user was logged in and could not be logged out
echo "Could not log you out.";
}
}
else
{
// not logged in and accessed this page
echo "You were not logged in.";
}
?>
I'm trying to make it so when you click log out the text saying you are logged in is replaced with "you are logged out"
at the moment the text pops up saying your logged out but the other text saying your logged in is still there.
site is http://www.irealms.co.uk/crimson