Posted: Sun May 18, 2003 9:05 am
almost.
Variable substitution only takes place in double-quoted literals, e.g.if you want to keep the single-quoted literals trysee: http://www.php.net/manual/en/language.t ... ing.syntax
puts <img src="$row['Anime_id'].jpg" /> to the output-stream.echo '<img src="$row['Anime_id'].jpg" /> ';
Variable substitution only takes place in double-quoted literals, e.g.
Code: Select all
echo "<img src="$row[Anime_id].jpg" /> ";Code: Select all
echo '<img src="', $row['Anime_id'], '.jpg" /> ';