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Posted: Sun May 18, 2003 9:05 am
by volka
almost.
echo '<img src="$row['Anime_id'].jpg" /> ';
puts <img src="$row['Anime_id'].jpg" /> to the output-stream.
Variable substitution only takes place in double-quoted literals, e.g.

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echo "<img src="$row[Anime_id].jpg" /> ";
if you want to keep the single-quoted literals try

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echo '<img src="', $row['Anime_id'], '.jpg" /> ';
see: http://www.php.net/manual/en/language.t ... ing.syntax