Page 1 of 1
Simple replacement question
Posted: Wed Feb 18, 2009 1:37 pm
by cjswanson1355
I am trying to modify a login screen to prevent people from adding their e-mail to the end of their login name. Basically, I want
cjswanson1355@hotmail.com
to be filtered and return
cjswanson1355
But I am having difficulty in finding exactly what function I am supposed to be using.
Re: Simple replacement question
Posted: Wed Feb 18, 2009 1:45 pm
by requinix
You can filter out a @ (and everything after) with substr and strcspn:
Code: Select all
$name = "cjswanson1355@hotmail.com";
echo substr($name, 0, strcspn($name, "@"));
Re: Simple replacement question
Posted: Wed Feb 18, 2009 1:48 pm
by greyhoundcode
How about something like:
Code: Select all
function Filter_Email($email)
{
return substr($email, 0, strpos($email, '@'));
}
echo Filter_Email('jobby@toilet.net');
// Output:
// jobby
Re: Simple replacement question
Posted: Wed Feb 18, 2009 2:03 pm
by requinix
Same thing, different function

Re: Simple replacement question
Posted: Thu Feb 19, 2009 5:23 am
by greyhoundcode
Yeah, wouldn't have bothered except it didn't look like anyone had answered when I started my reply
