hello
i want 2 return true/false return from Ajax function
function valid(){
if(document.frm1.name.value==""){
document.frm1.name .focus();
alert("Please enter name");
return false;
}
check_present_user(url,"GET","message_div");
/* how to get return value & check*/
if(document.frm1.address.value==""){
document.frm1.address.focus();
alert("Please enter address");
return false;
}
return true;
}
function submitForm(){
if(valid()==true){
document.frm1.submit();
}
}
pls help me
thank you
how to return value from ajax
Moderator: General Moderators
-
shuchitaumehta
- Forum Newbie
- Posts: 15
- Joined: Tue Jul 01, 2008 2:10 am
Re: how to return value from ajax
There is no ajax call in the code you provided.
Start by reading this tutorial by Mozilla - http://developer.mozilla.org/en/docs/AJ ... ng_Started
You may want to use a javascript library to handle your ajax requests, such as jQuery - http://jquery.com
Start by reading this tutorial by Mozilla - http://developer.mozilla.org/en/docs/AJ ... ng_Started
You may want to use a javascript library to handle your ajax requests, such as jQuery - http://jquery.com
Re: how to return value from ajax
When you say user already present, do you mean to check if the user is logged in?thank u for replay
i tried with javascript variable but its not secure
it shows all values in view source
i want to check user already present/ not before submitting form
if u have such example with jquery or any thing else
can u please help me
thank you
-
shuchitaumehta
- Forum Newbie
- Posts: 15
- Joined: Tue Jul 01, 2008 2:10 am
Re: how to return value from ajax
hi,pytrin wrote:When you say user already present, do you mean to check if the user is logged in?thank u for replay
i tried with javascript variable but its not secure
it shows all values in view source
i want to check user already present/ not before submitting form
if u have such example with jquery or any thing else
can u please help me
thank you
no
its register form
user name must be unique
so when new user enter user name i m checking this in db
if its present in db then it says user already present please enter another user name
in such a case i want whole db data
if i take this in javascript variable / cookie
user can see whole data its not secure way
so what should i do..?
thank you
Re: how to return value from ajax
Ok, an example with jQuery:
Suppose you have this simplified register form with a user-name input -
You want to check if the user name is taken when the user submits the form. First you intercept the form submit event:
You will need to also create the script that checks the user name against the database (in my example I named it check_username.php). It will recieve the username via the $_GET superglobal. Something like:
check_username.php
Suppose you have this simplified register form with a user-name input -
Code: Select all
<form action="register.php" method="post" id="registerForm">
User name: <input type="text" name="username" /> <br />
<input type="submit" value="Register!" />
</form>
Code: Select all
<script type="text/javascript">
$(document).ready(function() { //This will make sure the code inside runs only when the DOM is ready
$('form#registerForm').submit(function(event){ //Intercept the submit event for our form
var form = this;
event.preventDefault(); //Prevent the form from submitting while we check the user name
var username = $("input[name='username']",this).val(); //Extract the user-name value
$.ajax({
url: 'check_username.php', //This is the location of the script that will check if the user name exists in the database
data: 'username=' + username,
success: function(msg) { //This callback will handle the results of the check
if(msg == 1) { //We'll define a return value of 1 to confirm the user name is available
form.submit(); //Submit the form
} else {
// show an error message
}
}
});
});
});
</script>
check_username.php
Code: Select all
if($_SERVER['REQUEST_METHOD'] == 'GET') {
$username = $_GET['username'];
// Check if exists in the database, output '1' if available
}
-
shuchitaumehta
- Forum Newbie
- Posts: 15
- Joined: Tue Jul 01, 2008 2:10 am
Re: how to return value from ajax
thanks a lotpytrin wrote:Ok, an example with jQuery:
Suppose you have this simplified register form with a user-name input -You want to check if the user name is taken when the user submits the form. First you intercept the form submit event:Code: Select all
<form action="register.php" method="post" id="registerForm"> User name: <input type="text" name="username" /> <br /> <input type="submit" value="Register!" /> </form>You will need to also create the script that checks the user name against the database (in my example I named it check_username.php). It will recieve the username via the $_GET superglobal. Something like:Code: Select all
<script type="text/javascript"> $(document).ready(function() { //This will make sure the code inside runs only when the DOM is ready $('form#registerForm').submit(function(event){ //Intercept the submit event for our form var form = this; event.preventDefault(); //Prevent the form from submitting while we check the user name var username = $("input[name='username']",this).val(); //Extract the user-name value $.ajax({ url: 'check_username.php', //This is the location of the script that will check if the user name exists in the database data: 'username=' + username, success: function(msg) { //This callback will handle the results of the check if(msg == 1) { //We'll define a return value of 1 to confirm the user name is available form.submit(); //Submit the form } else { // show an error message } } }); }); }); </script>
check_username.phpCode: Select all
if($_SERVER['REQUEST_METHOD'] == 'GET') { $username = $_GET['username']; // Check if exists in the database, output '1' if available }