this checks user name and password and show form
Code: Select all
<head>
<title>login page</title>
</head>
<body bgcolor="black" style="color:gray">
<form action="index.php" method=get>
<h1 align="center" style="color:gray" >Welcome to this simple application</h1>
<?php
session_start();
if($_SESSION["logged"])
{
print_secure_content();
}
else {
if(!$_SESSION["logging"])
{
$_SESSION["logging"]=true;
loginform();
}
else if($_SESSION["logging"])
{
$number_of_rows=checkpass();
if($number_of_rows==1)
{
$_SESSION[user]=$_GET[userlogin];
$_SESSION[logged]=true;
print"<h1>you have loged in successfully</h1>";
print_secure_content();
}
else{
print "wrong pawssword or username, please try again";
loginform();
}
}
}fucntion login form
Code: Select all
function loginform()
{
print "please enter your login information to proceed with our site";
print ("<table border='2'><tr><td>username</td><td><input type='text' name='userlogin' size'20'></td></tr><tr><td>password</td><td><input type='password' name='password' size'20'></td></tr></table>");
print "<input type='submit' >";
print "<h3><a href='registerform.php'>register now!</a></h3>";
}Code: Select all
function checkpass()
{
$servername="localhost";
$username="root";
$conn= mysql_connect($servername,$username)or die(mysql_error());
mysql_select_db("test",$conn);
$sql="select * from users where name='$_GET[userlogin]' and password='$_GET[password]'";
$result=mysql_query($sql,$conn) or die(mysql_error());
return mysql_num_rows($result);
}but i don't know how to get this
kindly help me