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Trig Ratio :\
Posted: Mon Aug 07, 2006 5:57 pm
by kaoskorruption
How do I solve a = sin ( b / c ) for b?
Posted: Mon Aug 07, 2006 6:00 pm
by Charles256
inverse sin(a)=b/c
c time sinverse sin(a)=b
if my mind is working right. :-d
Posted: Mon Aug 07, 2006 6:02 pm
by kaoskorruption
inverse sin(a)=b/c
Is that mathematically possible?
I'll try it out! Thanks very much =D
Update: This doesn't seem to work :\
Lemme ask the question different.
|\
|a\
|``\
|```\ b
|````\
|`````\
-----------
c
How do I find the length of side c assuming I know angle a and side b and that it is a right triangle?
Posted: Tue Aug 08, 2006 4:42 am
by Oren
c = b * sin(a)
